تست‌لایک محصول جدید و منحصر به فرد پرلایک است. در این صفحه دفترچه کنکور ارشد مهندسی کامپیوتر 1401 و در صفحات بعدی دفترچه کنکور ارشد مهندسی کامپیوتر سال‌های دیگر آورده شده است. علاوه بر امکان دانلود خود دفترچه سؤالات سنجش، کلیه سؤالات و شکل‌های مربوطه تک به تک با کیفیت بالا تایپ و رسم شده است و در زیر آن حل تشریحی اساتید مختلف یا حتی دانشجویان علاقه‌مند آورده شده یا بعداً توسط خود اساتید یا دانشجویان نخبه و علاقه‌مند اضافه خواهند شد. کلیه داوطلبان کنکور، راه حل همه اساتید مختلف را دیده و امکان افزودن راه حل یا اظهار نظر (Comment) در زیر هر راه حل را دارند. استاد یا ارائه دهنده راه حل می‌توانند به اظهار نظر یا ایراد یا ابهام مطرح شده از طرف داوطلبان پاسخ دهند.

زبان عمومی (انگلیسی)

زبان تخصصی (انگلیسی)

ریاضی عمومی ( 1 و 2 )

در دفترچه سؤالات کنکور کارشناسی ارشد مهندسی کامپیوتر 1403 دقیقاً 20 سؤال ریاضیات با ضریب 2 وجود دارد که 7 سؤال آن متعلق به درس ریاضی عمومی (1 و 2) و 7 سؤال آن مربوط به درس آمار و احتمال مهندسی و 6 سؤال دیگر به ریاضیات گسسته مربوط می‌شود.

آمار و احتمال مهندسی

ریاضیات گسسته

نظریه زبان‌ها و ماشین‌ها

سیگنال‌ها و سیستم‌ها

ساختمان داده‌ها

طراحی الگوریتم

هوش مصنوعی

مدار منطقی

معماری کامپیوتر

الکترونیک دیجیتال

سیستم‌های عامل

شبکه‌های کامپیوتری

پایگاه داده‌ها

PART A:  Vocabulary
Directions:  Choose the word or phrase  (1),  (2),  (3),  or (4)  that best completes  each sentence.  Then mark the answer on your answer sheet

PART A:  Vocabulary

PART B: Cloze Test
Directions: Read the following passage and decide which choice (1), (2), (3), or (4) best fits each space.  Then mark the correct choice on your answer sheet.

PART B: Cloze Test

PART C: Reading Comprehension
Directions: Read the following three passages and answer the questions by choosing the best choice (1),  (2), (3), or (4).  Then mark the correct choice on your answer sheet.
PASSAGE 1:

When a user enters a query into a search engine (typically by using keywords),  the engine examines its index and provides a listing of best-matching web pages according to  its  criteria,  usually  with  a  short  summary  containing  the  document  title  and sometimes parts of the text. The index is  built from the information stored and the method  by  which  the  information  is  indexed.  The  usefulness  of a  search  engine depends on the relevance of the results set it gives back. For instance, there may be millions of web pages that include a particular word or phrase, but some pages may be more  relevant,  popular,  or  authoritative  than  others.  Most  search  engines  employ methods to rank the results to list the "best" results first. How a search engine decides which pages are the best matches, and in what order the results should be presented, varies widely from one engine to another. Also, search engine ranking methods change over time as the way users interact with internet services changes and new techniques evolve.
Many search engines, such as Google and Bing provide customized results based on the user's activity history. This leads to an effect that is called a filter bubble.  The
term describes a phenomenon  in which websites use algorithms to selectively guess what information a user would like to see,  based on information about the user (such as location, past click behavior and search history).  As a result,  websites tend to show 
only  information  that agrees  with the  user's  past  viewpoint,  effectively isolating  the user in a bubble that tends to exclude contrary information.



PART C: Reading Comprehension Passage 1

PART C: Reading Comprehension
Directions: Read the following three passages and answer the questions by choosing the best choice (1),  (2), (3), or (4).  Then mark the correct choice on your answer sheet.
To "recover"  data from  a bad  sector, one would  simply need  to issue  the Read Long command  instead  of the "normal"  Read  Sectors  command. That  is really  it!  It is so simple that any software developer  who is familiar with hard drives can do it. And sure enough,  more and  more data  recovery  tools  now come  with a Bad  Sector Recovery option.  In fact,  if  a tool  does not have a bad  sector recovery  feature,  it automatically falls into a second-grade  category.
Error checking  and correction  algorithms  were implemented  for a reason,  which is data  integrity.  When  a hard  drive  reads  a  sector  with  the  Read  Long  command,  it disables  these algorithms  and hence  there is no way to prove  that  you get valid data. Instead,  you get something,  which may or may not resemble your customer's data.
Tests in our lab  had shown that this approach allows you to get much more random bytes than  anything  else. Yes, there  are cases  where this approach  allows recovering original  data from  a sector.  But these  cases  are extremely  rare  in real  data recovery scenarios, and even then, only a part of the recovered  sector will contain valid data.
There  are tools  that claim better  bad  sector recovery.  But  they utilize  a statistical
approach,  an algorithm  where the tool reads the bad sector a number of times and then reconstructs  the  "original"   sector  by  locating  the  bits  that  occur  most  often  in  the

sector. While these tools claim this approach could improve the outcome, there is no evidence to back up the validity of such claims. Furthermore, re-reading the same spot many times while the hard drive is failing is a reliable way to cause permanent damage to the media or heads.

PART C: Reading Comprehension Passage 2

PART C: Reading Comprehension
Directions: Read the following three passages and answer the questions by choosing the best choice (1),  (2), (3), or (4).  Then mark the correct choice on your answer sheet.
There are two important types of packet networks: connectionless packet networks and connection-oriented  packet  networks.  Connectionless  packet  networks  operate  in a way analogous to the post office. Connectionless  networks offer  best effort packet• delivery service.  Connectionless  packets are launched  into the network with a large and powerful header that contains all the information necessary to deliver the packet, whatever  its  destination.  As  a by-product  of  their  connectionless  nature,  it  is  not possible  to guarantee  performance  or reserve  network  resources  for  any particular communication, so connectionless networks do not support real-time services reliably. The switches in the network are stateless. When the network is subjected to overload, packets are buffered for later delivery.  If the buffer capacity is exceeded,  the packets are discarded. In connectionless networks there is  no guarantee that all packets  will traverse the same network path and be subject to the same delays. If a communication requires the transmission  of a series of packets,  it is up to the end stations  to ensure that the sequence is preserved.
Connection-oriented  packet networks have similarities  with both circuit networks
and packet  networks.  They  are like circuit networks  in that  a connection,  called  a virtual circuit, must be established before data can be transported.  Network nodes are 
prepared  to support  virtual circuits, and they devote resources  to them. The resources include  buffer  memory  and  link  bandwidth.  Assumptions  are  made  about the  traffic likely to be contributed  by a11 the sources, and the network  may overload  if a11 sources begin  sending  packets   at  their  peak  rate.  Occasional  pileups   of  traffic  are  to  be expected  and  are handled  by  maintaining  local  memory  to buffer  packets  until  it is possible  to transmit  them.  The  network  is  not  stateless.  When  all  the resources  are committed,  the  network   may  deny  requests   to  establish  new  virtual  circuits.  The headers    of   connection-type   packet    networks    can    be    shorter   than    those    of connectionless   networks  because  the  addressing  portion  of the  header  needs  only  to distinguish   each  virtual  circuit  from  each  other  established   on  common  links  and switch ports.

PART C: Reading Comprehension Passage 3

کنکور ارشد مهندسی کامپیوتر 1401

بزودی

اگر P(E)=P(F)=0,6 و P(E∣F)=0,8 باشد، کدام مورد درست است؟

حل تشریحی سوال شماره 38 آمار و احتمال مهندسی

کنکور ارشد مهندسی کامپیوتر 1401

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